2(1^2)-5y+2=0

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Solution for 2(1^2)-5y+2=0 equation: 



2(1^2)-5y+2=0

We add all the numbers together, and all the variables

-5y+443=0

We move all terms containing y to the left, all other terms to the right

-5y=-443

y=-443/-5

y=88+3/5

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